Can you answer this Question????

mashmahesh · #1 (**permalink**) 23-07-2008, 12:53 PM

Good Question asked for recruitment

MNC recruitment contained this Q.

Two batsmen batting in 94 not out. The team needs 7 runs to win. Only 3 balls left. Both batsmen remain unbeaten on 100. How is it possible?

seelujangra · #2 (**permalink**) 23-07-2008, 12:56 PM

it is really tuff to answer it..

i m still thinking on it.

shinmv · #3 (**permalink**) 23-07-2008, 01:10 PM

ball 1. 1st bt'man - got six and reached 100
ball 2. 1st bt'man- trying for six but he lost the wicket by a catch but both the batsman corssed each other ( no runs , still need 1 run to win, but 2nd batman on strike with 94)
ball 3. 2nd bt'man got six and reached 100- won the match too

Hope this would be the ans ...........
Regds
Shin

mashmahesh · #4 (**permalink**) 23-07-2008, 01:23 PM

Dear shin

Both were unbeaten on 100. But good try... keep it up
regards
mahesh

supriyamanocha · #5 (**permalink**) 23-07-2008, 01:35 PM

2 possibilities:
First one
1st batsman hits the ball and runs for 3 runs, but one run is short run. Fielder throws the ball and is overthhrown for 4 runs - actual runs scored = 6 becoz of 1 short run.

But now the 2nd batsman is on crease and he hits a six at the next ball...

Both batsmen at 100, not beaten

Second Scenario

It starts raining at 46.5 overs and the game is stopped for some time. According to Duckworth Lewis rule, they have to score 7 runs off 3 balls to overcome the lost time.

the first batsman hits a 6 and reaches hundred. At the start of new over, 2nd batsman is at the crease and hits a six, making it a century for him.

Both the batsmen remain unbeaten on 100.

s_shalu · #6 (**permalink**) 23-07-2008, 02:53 PM

Mahesh,
Hi.
I believe there are many possiblities and ways to solve it..
A. one six and other balls just played without getting any run, thus making 94+6+0+0 = 100
B .2nd Solution -score of 3 balls as under
4 - 2 - 0
C.3rd Solution-score of remaining 3 balls as : 4 - 1 -1

Supriya's answer is apt too.

these are the possible answers that i could think of. I stand to be corrected! Well ,what's the answer???

supriyamanocha · #7 (**permalink**) 23-07-2008, 03:16 PM

hi Shalu...

u did not read the question properly i guess.... BOTH the batsman raech 100 UNBEATEN...

so ur answers are not correct... but well tried...

s_shalu · #8 (**permalink**) 23-07-2008, 03:20 PM

Thanks , Supriya! But I tried..which is more important,will think over it again. Again, thanx.

supriyamanocha · #9 (**permalink**) 23-07-2008, 03:27 PM

yeah of course Shalu... trying is more important than anything else....
u tried well.....

c_kamane · #10 (**permalink**) 23-07-2008, 03:48 PM

Mahesh,
Hi.
I believe there are many possiblities and ways to solve it..
As three balls are remaining :
Ball 1 = 4 runs
Ball 2 = Wide ball + 2 runs

Bats man 1 =100 runs

Ball 2 = bys bats man cross 1 run to team.

Ball 3 = Bats 2 hits Six

Hope its correct.

Supriya's answer is apt too right.

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